Question

The cross lines indicate deletion of the nucleotides. What type of mutation is this? What is the resulting polypeptide sequence?

3' - GTT - TAC - CTT --CTC - TCC - TCA - GAC - ATC - GCA - 5' (Template strand). (In the picture the CTC - T have a line through them)

5' - CAA - ATG - GAA ---GAG-AGG- AGT - CTG - TAG - CGT - 3' (Non-template/Coding strand). (in the picture the GAG- A have a line through them)

Answer:It's a ____________________mutation.

Final polypeptide sequence is N' - Met - Glu _________________ ________________ _________________ _________________ - C'

Please help me..

Answer 1

QUESTION-1

ANSWER

Template strand :

3' - GTT - TAC - CTT -CTC - TCC - TCA - GAC - ATC - GCA - 5'

Non-template/Coding strand :

5' - CAA - ATG - GAA -GAG-AGG- AGT - CTG - TAG - CGT - 3'

This is a frameshift mutation.

Final template DNA strand

3' - GTT - TAC - CTT -CCT- CAG- ACA- TCG -CA - 5'

mRNA Sequence

5'- CAA- AUG- GAA- GGA- GUC- UGU- AGC-3'

Final polypeptide sequence

N' - Met - Glu - Gly- Val- Cys- Ser- C'

EXPLANATION

AUG is the ntitiation codon for translation.

In frameshift mutation nucleotide bases are being added or deleted which leads to the production of a different polypeptide from the original one.

The peptide produced from this type of mutation is functionally inactive.

GOOD LUCK.