Question

A 11-cm-long, 180 g rod is pivoted at one end. A 19 g ball of clay is stuck on the other end.

What is the period if the rod and clay swing as a pendulum?

Answer 1

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Given that,

Length of the rod, L= 11 cm = 0.11 m

Mass of the rod, M= 180 g =0.180 kg

Mass of the clay ball, m= 19 g= 0.019 kg

Therefore, moment of intertia of the rod is given by,

Moment of inertia of the clay ball at the end is given by,

Hence, total moment of inertia of the rod-ball system,

We know that the angular frequency is given by,

Also, we have,

Hence period of the rod and clay ball is

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