Question

TRUE/FALSE QUESTIONS Question 1 Spontaneous processes proceed without outside intervention once initiated. Yet, spontaneous processes are...

TRUE/FALSE QUESTIONS

Question 1
Spontaneous processes proceed without outside intervention once initiated. Yet, spontaneous processes are not always rapid.

Group of answer choices

True

False

Question 2
The sign of ∆G tells us how fast a reaction (or a process) might occur.

Group of answer choices

True

False

Question 3
The sublimation of dry ice (solid CO2), where CO2(s) LaTeX: \longrightarrow ⟶ CO2(g), has ∆S>0, ∆H>0, and ∆G<0 at 25°C.

Group of answer choices

True

False

Question 4
If a reaction is spontaneous based on favorable entropy change (i.e., ∆S>0) at a given temperature, then the reverse of that reaction should also be spontaneous (i.e. ∆S>0) at the same temperature.

Group of answer choices

True

False

Question 5
During digestion, complex carbohydrates decompose into simple sugars that our body can use and metabolize. As a result, the carbohydrates experience a reduction in its entropy.

Group of answer choices

True

False

Question 6
Precipitation reactions tend to have ∆S°rxn < 0 due to the formation of a solid precipitate from dissolved ions or molecules in the solution.

Group of answer choices

True

False

Question 7
Consider the following hypothetical, reversible reaction: A+BLaTeX: \longleftrightarrow ⟷C+D.

When ∆Grxn < 0 (negative) for this chemical reaction, then the reaction will proceed to the right toward products. When ∆Grxn > 0 (positive), however, the reaction will proceed to the left, toward reactants. Once the reaction reaches an equilibrium, ∆Grxn = 0.

Group of answer choices

True

False

Question 8
Exothermic reactions with a positive ∆S (i.e., ∆S>0) are spontaneous only at low temperature (T).

Group of answer choices

True

False

Question 9
Endothermic reactions are never spontaneous at any temperature (T) regardless the ∆S-value.

Group of answer choices

True

False

Question 10
At absolute zero temperature (i.e., 0.0 K), the entropy of a perfect crystal is zero where molecules are highly ordered and occupy the lowest vibrational, rotational and translational energy microstates (i.e., W=1 in Boltzmann equation).

Group of answer choices

True

False

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Question 10 statement is true

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