Estimate the pH of the resulting solution prepared by mixing 1.0 mole of solid disodium phosphate (Na2HPO4) and 1.25 mole of hydrochloric acid. The pKas of phosphoric acid are 2.1, 7.2, 12.4. Please explain each step
The reaction occurs:
HPO4-2 + H + = H2PO4-
All moles of HPO4-2 are neutralized and begins to form:
H2PO4- + H + = H3PO4
Then you have:
n H3PO4 = 0.25 mol
n H2PO4- = 0.75 mol
You have the expression:
pH = pKa + log (n H2PO4- / n H3PO4) = 2.1 + log (0.75 / 0.25) = 2.56
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Estimate the pH of the resulting solution prepared by mixing 1.0 mole of solid disodium phosphate...
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