A 500 mL flask was filled with 1.5 mol of OCl2, 0.70 mol of BrOCl and...
Suppose a 250. ml flask is filled with 1.8 mol of OC1, 0.70 mol of BroCl and 0.50 mol of BrCl. The following reaction becomes possible: Br2(g) + OC12(g) – Brocl(g) +BrCl(g) The equilibrium constant K for this reaction is 1.48 at the temperature of the flask. Calculate the equilibrium molarity of BroCl. Round your answer to two decimal places. x 5 ?
Suppose a 500.mL flask is filled with 1.9mol of Br2, 1.5mol of OCl2 and 0.40mol of BrOCl. The following reaction becomes possible: +Br2gOCl2g +BrOClgBrClg The equilibrium constant K for this reaction is 5.17 at the temperature of the flask. Calculate the equilibrium molarity of BrOCl. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 0.90 mol of OC1,, 0.20 mol of BroCl and 1.4 mol of BrCl. The following reaction becomes possible: Br2(g) +OC12(g) =BroCl(g) +BrCl(g) The equilibrium constant K for this reaction is 0.798 at the temperature of the flask. Calculate the equilibrium molarity of Br2. Round your answer to two decimal places. IM xs ?
Suppose a 500.mL flask is filled with 0.90mol of Br2, 0.30mol of OCl2 and 1.5mol of BrCl. The following reaction becomes possible: +Br2gOCl2g +BrOClgBrClg The equilibrium constant K for this reaction is 0.841 at the temperature of the flask. Calculate the equilibrium molarity of OCl2. Round your answer to two decimal places
Suppose a 500. ml flask is filled with 1.3 mol of Br2, 2.0 mol of OC1, and 1.2 mol of BrCl. The following reaction becomes possible: Br2(g) + OC12(g) = BroCl (g) + BrCl (g) The equilibrium constant K for this reaction is 0.766 at the temperature of the flask. Calculate the equilibrium molarity of OC12. Round your answer to two decimal places. xs ?
Suppose a 250. mL flask is filled with 2.0 mol of OCl 2 , 1.4 mol of BrOCl and 1.5 mol of BrCl . The following reaction becomes possible: + Br 2 g OCl 2 g + BrOCl g BrCl g The equilibrium constant K for this reaction is 7.62 at the temperature of the flask. Calculate the equilibrium molarity of Br 2 . Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 1.9 mol of Cl2, 0.70 mol of HCl and 1.7 mol of CCI4. The following reaction becomes possible Cl2(g)+ CHCI3)HCI (g)+CCI4g) The equilibrium constant K for this reaction is 7.09 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places
Suppose a 500. mL flask is filled with 0.70 mol of H2 and 0.60 mol of HI. The following reaction becomes possible: -2H1(g) The equilibrium constant K for this reaction is 2.38 at the temperature of the flask. Calculate the equilibrium molarity of H2. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 1.6 mol of O, and 0.70 mol of NO. The following reaction becomes possible: N2(g)02g)2NO (g) The equilibrium constant K for this reaction is 9.43 at the temperature of the flask Calculate the equilibrium molarity of NO. Round your answer to two decimal places. Ом X
Suppose a 500. mL flask is filled with 0.70 mol of NO2, 2.0 mol of NO and 0.90 mol of CO2. The following reaction becomes possible: NO2(e)+Co(g)NO(g)+Co,(g) The equilibrium constant K for this reaction is 0.331 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places.