Question

The length of time taken by students on a statistics exam is normally distributed with a...

The length of time taken by students on a statistics exam is normally distributed with a mean of 45 minutes and a standard deviation of 3 minutes. What proportion of students will finish the exam in 50 minutes or less?

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Answer #1

Solution :

Given that,

mean = = 45

standard deviation = =3   

P(X<50 ) = P[(X- ) / < (50-45) /3 ]

= P(z < 1.67)

Using z table

=0.9525

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