2.) The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean of 3.2 pounds and standard deviation of 1 pound. what percentage ( to one decimal place) of samples of 4 fish will have sample means between 3.0 and 4.0 pounds?
2.) The owner of a fish market has an assistant who has determined that the weights...
The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed with a mean of 3.2 pounds and a standard deviation of .8 pounds. There is an 85% chance that the sample mean for a sample size of 64 is below how many pounds?
1.) Major league baseball salaries averaged $1.5 million with a standard deviation of $1 million in 1994. Suppose a sample of 100 major league players was taken. Find the approximate probability that the average salary of the 100 players exceeded $1.27 million. 2.) The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean of 3.2 pounds and standard deviation of 1 pound. what percentage ( to one decimal...
The owner of a fish market determined that the mean weight for a catfish is 3.2 pounds with a standard deviation of 0.8 pound. Assuming the weights of catfish are normally distributed, what is the probability that a randomly selected catfish will weigh between 2 and 4 pounds?
The owner of a fish market finds that the mean weight for a catfish is 3.2 pounds with a standard deviation of 0.8 pounds. Assume that the weights of the catfish are normally distributed. You buy a sample of 25 catfish. What is the probability that the mean weight of the 25 catfish is less than 3 pounds?
10) In a left-tailed test comparing two means with unknown variances assumed to be equal, the test statistic was t = -1.81 with sample sizes of n1 = 8 and n2 = 12. The p-value would be: Select one: a. between .025 and .05 b.between .01 and .025 c.between .05 and .10 d. Must know α to answer The owner of a fish market determined that the weights of catfish are normally distributed, with a mean of 3.2 pounds and...
Dr. I.C. Trout, a professional ichthyologist, is studying a population of catfish with his assistant, Etta Bass. Trout and Bass have established the mean weight for a catfish is 3.2 pounds, with a standard deviation of 0.8 pounds. Weights of catfish are normally distributed. Solve the following: A. What is the probability that a catfish will weigh more than 4.4 pounds? B. What is the probability that a catfish will weigh between 3 and 5 pounds? C. What is the...
Bass - Samples: The bass in Clear Lake have weights that are normally distributed with a mean of 2.3 pounds and a standard deviation of 0.6 pounds. What percentage of all randomly caught groups of 3 bass should weigh between 2.1 and 2.5 pounds? Enter your answer as a percentage rounded to one decimal place. %
The owner of a fish market determined that the mean weight for a catfish is 3.2 pounds assuming that the weight of a catfish follows a normal distribution and its standard deviation is unknown. He also knew that that probability of a randomly selected catfish that would weigh more than 3.8 pounds is 20% and the probability that a randomly selected catfish that would weigh less than 2.8 pounds is 30%. What is the probability that a randomly selected catfish...
Bass - Samples: The bass in Clear Lake have weights that are normally distributed with a mean of 2.2 pounds and a standard deviation of 0.8 pounds. Suppose you catch a stringer of 6 bass with a total weight of 16.5 pounds. Here we determine how unusual this is. (a) What is the mean fish weight of your catch of 6? Round your answer to 1 decimal place. (b) If 6 bass are randomly selected from Clear Lake, find the...
Bass - Samples: The bass in Clear Lake have weights that are normally distributed with a mean of 2.3 pounds and a standard deviation of 0.8 pounds. What percentage of all randomly caught groups of 3 bass should weigh between 2.0 and 2.6 pounds? Enter your answer as a percentage rounded to one decimal place. I get so far but I can't determine the Z-score from the z-score table because it only goes up to 2 decimal places.