The owner of a fish market determined that the mean weight for a catfish is 3.2 pounds with a standard deviation of 0.8 pound. Assuming the weights of catfish are normally distributed, what is the probability that a randomly selected catfish will weigh between 2 and 4 pounds?
The owner of a fish market determined that the mean weight for a catfish is 3.2...
The owner of a fish market finds that the mean weight for a catfish is 3.2 pounds with a standard deviation of 0.8 pounds. Assume that the weights of the catfish are normally distributed. You buy a sample of 25 catfish. What is the probability that the mean weight of the 25 catfish is less than 3 pounds?
2.) The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean of 3.2 pounds and standard deviation of 1 pound. what percentage ( to one decimal place) of samples of 4 fish will have sample means between 3.0 and 4.0 pounds?
10) In a left-tailed test comparing two means with unknown variances assumed to be equal, the test statistic was t = -1.81 with sample sizes of n1 = 8 and n2 = 12. The p-value would be: Select one: a. between .025 and .05 b.between .01 and .025 c.between .05 and .10 d. Must know α to answer The owner of a fish market determined that the weights of catfish are normally distributed, with a mean of 3.2 pounds and...
The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed with a mean of 3.2 pounds and a standard deviation of .8 pounds. There is an 85% chance that the sample mean for a sample size of 64 is below how many pounds?
The owner of a fish market determined that the mean weight for a catfish is 3.2 pounds assuming that the weight of a catfish follows a normal distribution and its standard deviation is unknown. He also knew that that probability of a randomly selected catfish that would weigh more than 3.8 pounds is 20% and the probability that a randomly selected catfish that would weigh less than 2.8 pounds is 30%. What is the probability that a randomly selected catfish...
Dr. I.C. Trout, a professional ichthyologist, is studying a population of catfish with his assistant, Etta Bass. Trout and Bass have established the mean weight for a catfish is 3.2 pounds, with a standard deviation of 0.8 pounds. Weights of catfish are normally distributed. Solve the following: A. What is the probability that a catfish will weigh more than 4.4 pounds? B. What is the probability that a catfish will weigh between 3 and 5 pounds? C. What is the...
1.) Major league baseball salaries averaged $1.5 million with a standard deviation of $1 million in 1994. Suppose a sample of 100 major league players was taken. Find the approximate probability that the average salary of the 100 players exceeded $1.27 million. 2.) The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean of 3.2 pounds and standard deviation of 1 pound. what percentage ( to one decimal...
The weight, in kg, of fish in a lake follows a normal distribution with mean 2 and standard deviation 0.5 a) What is the probability that a randomly selected fish weights less than lkg? b) Find the value, w, of the weight of a fish such that 95% of the fish weigh ess than w.
a) Suppose that the weight of the adult male wombat is normally distributed with mean 8,6 pounds and standard deviation 1.1 pounds. What is the probability that a randomly selected adult male wombat will weigh at least 9.5 lbs? Rounded to the nearest.01 pound, what is the 85th percentile of adult male wombat weight? A sample of 50 wombats is chosen. What is the probability that its mean is less than 8.3 pounds? To conduct a new study to find...
1) The weights of the fish in a certain lake are normally distributed with a mean of 20 lb and a 1). standard deviation of 9. If 9 fish are randomly selected, draw, label and shade the normal curve, find the z-scores, and find the probability that the mean weight will be between 17.6 and 23.6 lb. Draw, label, and shade: Z-scores: P(17.6<x< 23.6)