Question

1. How do you get the expected from the observed in order to perform a chi...

1. How do you get the expected from the observed in order to perform a chi square with the following data?

Original cross was between a mutant male that had white eyes and vestigial wings and a female that had red eyes and normal wings.

F1 Progeny Class Data Results

Phenotype

(Eye, Wing)

Wild Type eye, Wild Type wings

Wild Type eye,

Vestigial wings

White eye,

Wild Type wings

White eye, Vestigial wings

Male

242

2

1

8

Female

250

2

0

9

Total

492

4

1

17

Total Progeny: 514

0 0
Add a comment Improve this question Transcribed image text
Answer #1

In this case, the maximum no. of progeny are from red eyes and normal wings so we assume they are the dominant genes.

Let us denote red eyes by RR, white eyes by rr, normal wings by NN and vestigial wings by nn.

The Cross is as follows: RRNN(female) x rrnn(male)

RN RN
rn RrNn RrNn
rn RrNn RrNn

Expected frequency according to this cross should be 1:0 = Wild type eyes and Wild Type wings: others

The expected no. of progeny for:

Wild Type eye, Wild Type wings = 1x514 = 514

Wild Type eye,Vestigial wings = 0

White eye, Wild Type wings = 0

White eye, Vestigial wings = 0

These can now be used to find the chi-squared function.

Add a comment
Know the answer?
Add Answer to:
1. How do you get the expected from the observed in order to perform a chi...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • You are working with recessive mutations at two genes in Drosophila: the fused mutation fu causes...

    You are working with recessive mutations at two genes in Drosophila: the fused mutation fu causes fused wings and the garnet mutation g causes bright red eyes. You cross a true-breeding strain of wild-type flies with a true-breeding strain with garnet eyes and fused wings. You then cross an F1 female to a true-breeding male with fused wings and garnet eyes. #1) Choose which phenotype(s) in the F2 progeny result from recombination: A) fused wing, wild-type eye B) wild-type wing,...

  • Genetic Linkage The six genes listed below are all located on Chromosome 2 of Drosophila melanogaster....

    Genetic Linkage The six genes listed below are all located on Chromosome 2 of Drosophila melanogaster. Your goal is to construct a genetic map of Chromosome 2. That is, determine the order of these genes along chromosome 2 and the map distance in centimorgans between each gene. To complete this task, you will be given the results of a variety of two-point test crosses involving these genes. For each test cross you may assume that the female is heterozygous and...

  • Mutant Female x Wild Type Male Wild Type Wing & Red Eyes Females 121 Mutant Wing...

    Mutant Female x Wild Type Male Wild Type Wing & Red Eyes Females 121 Mutant Wing & White Eyes Males 95 Wild Type Female x Mutate Male Wild Type Wing & Red Eyes Females 43 Wild Type Wing & Red Eyes Males 45 Blue Label Red Label F1 Female x Mutant Male F1 Female x Mutant Male Wild Type Wing & Red Eyes Female 91 Wild Type Wing & Red Eyes Female 42 Wild Type Wing & Red Eyes Males...

  • You mate two Fi flies and observe the following results of the F2 generation. Mal Tan body Male. ...

    We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this imageYou mate two Fi flies and observe the following results of the F2 generation. Mal Tan body Male. Wid Type Mae Tan body Female: Wild Type Female: Tan body 0 25 0 254 0 2400 Total 120 is. Describe the phenotypes and ratios obtained in the F generation. What does this result tell you about the sex chromosome location of the tan...

  • could someone help me figure out how to do these pleaseeee A female fruit fly who...

    could someone help me figure out how to do these pleaseeee A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: # offspring, body color. eye color. wing length 411 gray red long 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial...

  • FInd F1 and parental based off of F2 data Phenotype Delivered Counts: Male Red Eyes &...

    FInd F1 and parental based off of F2 data Phenotype Delivered Counts: Male Red Eyes & Normal Wings 269 Male Red Eyes & Vestigial Wings 90 Male White Eyes & Normal Wings 252 Male White Eyes & Vestigial Wings 77 Female Red Eyes & Normal Wings 545 Female Red Eyes & Vestigial Wings 183 Female White Eyes & Normal Wings 11 Female White Eyes & Vestigial Wings 1

  • Normal eye color in flies is red. Mutant flies have brown eye color. Similarly, normal wing...

    Normal eye color in flies is red. Mutant flies have brown eye color. Similarly, normal wing length is long. Mutant flies have short wings. A female true breeding fly with brown eyes and short wings is crossed with a true breeding male with red eyes and long wings. In the F1 the female flies are red eyed and long winged. The male flies are red eyed and short winged. F1 males are crossed to F1 females Both sexes of F2...

  • The results for the F2 progeny are shown for a F1 cross using the two X-linked...

    The results for the F2 progeny are shown for a F1 cross using the two X-linked markers: w+ and m+. As shown in the figure, the F1 cross is between the following two parents: - a phenotypically wild-type (red eye, full wing), heterozygous female: w+m+/wm - a double mutant male (white eye, miniature wing): wm/Y Answer the following questions: 1) In the F1 cross, can you infer the genotype for the phenotype in the female? Why or why not? 2)...

  • Question 6: Imagine you a research student working in the lab of T.H. Morgan and are...

    Question 6: Imagine you a research student working in the lab of T.H. Morgan and are given the task of determining the recombination frequency of double mutants for eye color and wing type. You breed a female that is homozygous dominant for red eyes and normal wings with a male that has white eyes and vestigial wings. What phenotypes do you predict you will observe in the males of the F1 generation? a. All of the males will have white...

  • A Xw+m+Xwm female was mated to a XwmY male. Out of 1000 total F1 progeny there...

    A Xw+m+Xwm female was mated to a XwmY male. Out of 1000 total F1 progeny there were 230 flies that were otherwise wild type with white eyes and 240 flies that were otherwise wild type with miniature wings. What is the distance between the genes for eye color and wing length? A. 47 map units B. 24 map units C. 53 map units D. 23 map units

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT