Assume that long earlobes in humans is an autosomal dominant trait that exhibits 30% penetrance. A...
Assume that long earlobes in humans is an autosomal dominant trait that exhibits 30% penetrance. A person who is heterozygous for long earlobes mates with a person who is homozygous for normal earlobes.
What is the probability that their first child will have long earlobes?
Homework Answers
Answer:-
Given :-
Long earlobes in human are autosomal dominant
With 30 % penetrance
Let CC = dominant trait
cc= recessive trait ( homozygous normal)
Cc heterozygous trait
If a heterozygous ( Cc ) married with homozygous normal (cc)
That is. Cc. X. cc
F1. Cc. (Diseased) Cc.(diseased ) cc. (Normal) cc(normal )
Probability of there 1st child to have long earlobes is. = 2 /4 x30%
= 1/2 x 30%
= 15%
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