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The reaction SO2(g)+2H2S(g) ⇌ 3 S(s)+2H2O(g) is the basis of a suggested method for removal of SO2 , a pollutant that irritates airways causing coughing, from power-plant stack gases. The values below may be helpful when answering questions about the process.
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Assume that the partial pressure of sulfur dioxide, PSO2, is equal to the partial pressure of dihydrogen sulfide, PH2S, and therefore PSO2=PH2S. If the vapor pressure of water is 22 torr , calculate the equilibrium partial pressure of SO2 (PSO2) in the system at 298 K.
Express the pressure in atmospheres to two significant figures.
Calculate ΔG0rxn as below.
ΔG0rxn = ∑n.ΔG0f(products) - ∑n.ΔG0f(reactants)
where n denotes the number of mol(s) of reactant and product molecules. Therefore,
ΔG0rxn = [(3 mol S)*ΔG0f(S, s) + (2 mol H2O)*ΔG0f(H2O, g)] – [(1 mol SO2)*ΔG0f(SO2, g) + (2 mol H2S)*ΔG0f(H2S)]
= [(3 mol)*(0 kJ/mol) + (2 mol)*(-228.6 kJ/mol)] – [(1 mol)*(-300.4 kJ/mol) + (2 mol)*(-33.01 kJ/mol)]
= (-457.2 kJ) – (-300.4 kJ – 66.02 kJ)
= (-457.2 kJ) – (-366.42 kJ)
= -90.78 kJ
Determine the equilibrium constant for the reaction as
ΔG0rxn = -RTln Kp
where T = 298 K is the temperature of the reaction and Kp is the equilibrium constant for the reaction.
Plug in values and obtain
-90.78 kJ = -(8.314 J/mol.K)*(298 K)*ln Kp
======> (-90.78 kJ)*(1000 J)/(1 kJ) = -(2477.572 J/mol )*ln Kp
======> -9078 J = -(2477.572 J/mol)*ln Kp
======> ln Kp =(-9078 J)/(-2477.572 J/mol)
======> ln Kp = 3.6641 (ignore units)
======> Kp = exp(3.6641)
======> Kp = 39.02
Write down the expression for Kp as
Kp = (PH2O)2/(PSO2)(PH2S)2
Given the relation and PH2O = 22 torr (ignore units), we can write
39.02 = (22)2/(P)(P)2 (denote PSO2 = PH2S = P)
=====> 39.02 = (484)/(P)3
=====> P3 = 484/39.02 = 12.40
=====> P = 2.314 ≈ 2.3 (correct to 2 sig. figs)
The partial pressure of SO2 is 2.3 torr (ans).
The reaction SO2(g)+2H2S(g) ⇌ 3 S(s)+2H2O(g) is the basis of a suggested method for removal of...
The reaction SO2(g)+2H2S(g) ⇌ 3 S(s)+2H2O(g) is the basis of a suggested method for removal of SO2, a pollutant that irritates airways causing coughing, from power-plant stack gases. The values below may be helpful when answering questions about the process. Substance ΔG∘f (kJ/mol) ΔH∘f (kJ/mol) H2O(g) −228.6 −241.8 H2O(l) −237.1 −285.8 SO2(g) −300.4 −296.9 SO3(g) −370.4 −395.2 H2S(g) −33.01 −20.17 S(s) 0 0 PART A: Calculate the equilibrium constant Kp for the reaction at a temperature of 298 K. Express...
The reaction SO2(g)+2H2S(g)⇌3S(s)+2H2O(g) is the basis of a suggested method for removal of SO2 from power-plant stack gases. The values below may be helpful when answering questions about the process. Substance ΔG∘f (kJ/mol) ΔH∘f (kJ/mol) H2O(g) − 228.6 − 241.8 H2O(l) − 237.1 − 285.8 SO2(g) − 300.4 − 296.9 SO3(g) − 370.4 − 395.2 H2S(g) − 33.01 − 20.17 S(s) 0 0 Part A Calculate the equilibrium constant Kp for the reaction at a temperature of 298 Part D...
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(1) Consider SO2 (g) + 2H2S(g) = 3(g) + 2H2O(1) AH : (i) SO2 (g) = -296.8 KJ/mol (ii) H2S (g) = -20.4 KJ/mol (iii) H20 (1) = -285.84 KJ/mol AH for the above reaction is: (a) 234.08 KJ (b)-234.08 KJ (c) 31.36 kJ (d) -31.36 KJ (e) None (2) The above reaction is (a) Endothermic (b) Exothermic (c) entropic (3) in k = Ae Ea/RT, Ea is (a) Activation Energy (b) 8.314 J/mol.K (c) Rate constant (4) In a...
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