Labrador retrievers have the possible coat colors of black, brown, or golden. Two genes are involved in the color. A gives black and is dominant to a. When aa occurs, the color is determined by B/b genes. B is dominant for brown, but only if no A is present. The combination bb is epistatic to the A locus and gives golden regardless of the A/a alleles. Indicate the color of the parents given. Then work out the crosses with Punnett Squares and give the phenotypes and their ratios or numbers.
A_B_ = black
aaB_ = brown
A_bb = golden
aabb = golden
A.
Aabb = golden
aaBB = brown
| Gametes | aB |
| Ab | AaBb black |
| ab | aaBb brown |
Phenotypic ratio = 1 (black) : 1 (brown)
2.
AaBb = black
Aabb = golden
| Gametes | Ab | ab |
| AB | AABb black | AaBb black |
| Ab | AAbb golden | Aabb golden |
| aB | AaBb black | aaBb brown |
| ab | Aabb golden | aabb golden |
Phenotypic ratio = 3 (black) : 4 (golden) : 1 (brown)
Please give a high rating.
Labrador retrievers have the possible coat colors of black, brown, or golden. Two genes are involved...
In Labrador retrievers, coat color is determined by the interaction of two genes (pigment and deposition of pigment). This is called epistasis. Coat color can be black (B) or brown (b) and deposition of pigment into the hair shaft is deposited (E) or not deposited (e). If a retriever has the genotype where they have _ _ ee, then they will have a yellow coat regardless of what color they inherit (e.g., Bbee or bbee gives a Yellow lab). Calculate the phenotypic ratios of a cross between a...
Fur color in Labrador Retrievers is a Polygenic trait with Epistasis. There are two genes and two alleles for each gene: Gene 1: Gene 2: B = Black coat (dominant) T = Add pigment to fur (Dominant) b = Brown coat (recessive) t = No pigment (Recessive) (Yellow) Mate two retrievers with these genotypes: Male BbTt x Female bbTt. From the cross above, what is the probability of having a Brown Labrador Retriever puppy?
In Labrador retrievers, black coat color (B) is dominant to brown (b). Suppose that a black Lab is mated with a brown one and the offspring are 4 black puppies and 1 brown. What can you conclude about the genotype of the black parent?
Labrador retrievers may be black, brown or golden. While each color may breed true, many different outcomes occur if many different litters are examined from a variety of matings, where parents aren’t necessarily true breeding. Below are some of the multiple possibilities. Propose a mode of inheritance and determine the genotypes of the parents in the crosses. (4) a) Black x brown = all black b) Brown x Black = ½ black ½ brown c) Black ...
Laborador retrievers come in 3 colors-black, brown or golden. Gene B determines what color of pigment is produced, with black being dominant over brown. Gene C determines pigment deposition, with the prescense of the dominant allele resulting in pigment deposition and homozygous recessive resulting in a golden appearance (no deposition). a) which gene is epistatic to which? b) If a Bbcc individual is crossed with a bbCc, what proportion of the progeny will be black, brown of golden? c) you...
7) In Labrador retrievers, 2 independently assorting genes interact to generate coat color (B, b and E, e). The genotype B_E_ results in black coat; bbE_ results in chocolate coats; B_ee results in yellow coat; and bbee results in yellow coat. If you were a breeder, you might be especially interested in producing black and brown labs, since they might fetch the most money when sold. What proportion of these two phenotypes would you expect from the following crosses? a)...
The Labrador retriever's coat colours are black, yellow, and chocolate. s produced by the presence of a recessive epistatic gene, which has the effect of masking the black and chocolate colour genes. Black (B) is dominant to chocolate (b) Therefore, the possible genotypes and corresponding phenotypes are: Phenotype Black Brown Yellow Possible Genotypes G bb 41. Predict the percentage of offspring that would be black in colour for each of the following crosses. Record your answer as a whole number....
QUESTION 2 Coat color in Labrador retrievers is determined by two alleles at each of two loci Bb and Ee. Dihybrid crosses produce 9:3:4 black:chocolate:yellow offspring. What can be concluded about the B and E alleles with respect to coat color? They are epistatic They are not epistatic They are in the same biochemical pathway o They are in different biochemical pathways QUESTION 1 Consider a dihybrid cross between a purple long (PPLL) individual and a red, round individual (ppll)....
2. In Labrador dogs, there are 2 loci that determine coat color. The first locus, B is dominant to b. At least one B allele will produce black coat color, while the bb genotype produces a chocolate coat color. This first locus also determines nose color in Labradors: B_ black noses, and bb brown noses. The second locus has a genotype, ee, that is epistatic in nature. Any Labrador with an ee genotype will be yellow. A genotype containing at...
/ fn Labrador retrie brown coat color however, the E gene controls expression of the B gene. The B and E genes interact to yield 3 phenotypes: black (B_E), chocolate (bbE) and yellow ee). What is the phenotypic ratio of the pups that might result vers, the B allele confers black coat color and the b allele from a cross between a yellow female (Bbeo and a chocolate male (hb Be) Coat color in Labrador retrievers is an example of...