suppose you are going to create a 90% confidence interval for mean. if the sample size is 25, what would be the critical t values that you would need to use? sketch a picture showing t values
SOLUTION
n = 25
Degrees of freedom = df = n - 1 = 25 - 1 = 24
At 90% confidence level the t is ,
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
t
/2,df = t0.05,24 = 1.711 ( using student t
table)3
suppose you are going to create a 90% confidence interval for mean. if the sample size...
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