Question

Find the five problems with this program. Do not change the functionality or rewrite the program.

#include <iostream>

void multiply(int x = 1, int y);

int main()
{
int length, width, area;

cout << "Enter length and width of a rectangle ";
cin >> length, width;

area = multiply(length, width);

cout << "The area is " << area << endl;

area2 = multiply(width);

cout << "The second area is " << area2 << endl;

return 0;
}

void multiply(int x= 1, int y);
{
return x * y;
}

Answer 1

#include <iostream>

1) //here using namespace std; is required for cin,cout

void multiply(int x = 1, int y); 2) // return type should be integer

int main()
{
int length, width, area;

cout << "Enter length and width of a rectangle ";
cin >> length, width; 3) //here for taking input yoou should write like cin>>length>>width;

area = multiply(length, width); //the function type is void but here expecting return value.

cout << "The area is " << area << endl;

area2 = multiply(width); 4) //area2 variable is not declared and one more parameter required for function call

cout << "The second area is " << area2 << endl;

return 0;
}

void multiply(int x= 1, int y); 5) //remove semicolon from here to run whole function body
return x * y;
}

///////////////////////error free code////////////////////////

#include <iostream>
using namespace std;
int multiply(int x,int y);
int main()
{
int length, width, area,area2;
cout << "Enter length and width of a rectangle ";
cin >> length>>width;
area = multiply(length, width);
cout << "The area is " << area << endl;
area2 = multiply(length,width);
cout << "The second area is " << area2 << endl;
return 0;
}

int multiply(int x, int y)
{
return x * y;
}