Question

Refer back to the standard curve that you built previously (absorbance vs. concentration) The pH of...

Refer back to the standard curve that you built previously (absorbance vs. concentration)

The pH of a solution describes the concentration of H+ in a solution, where pH = -log[H+]. Note that this is a log10, not the natural log, so the inverse is [H+] = 10-pH. Acetic acid dissociates in water according to the following reaction:

-+CH3COOH (aq) ⇄ CH3COO (aq) + H (aq)

The pH of a 1.0 M solution of acetic acid is 2.37. What is the value of the equilibrium constant for the dissociation of acetic acid?

The equation of the standard curve I have is y = .027x+.0373

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Answer #1

concentration = 1.0 M

pH = 2.37

[H+] = 10^-pH

        = 10^-2.37

       = 4.266 x 10^-3 M

CH3COOH   ------------> CH3COO- (aq) + H+

1.0                                         0                     0

1.0 - x                                   x                      x

x = [H+] = 4.266 x 10^-3

Ka = x^2 / 1.0 - x

     = (4.266 x 10^-3)^2 / 1 - 4.266 x 10^-3

Ka = 1.8 x 10^-5

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