Transcribe the following DNA
1. 3’ – TAC CAC GTG GAC TGA GGA CTC CTC TTC AGA CGG CAA TGA – 5’
a. MRNA
b. 5’ - AUG GUG CAC CUG ACU CCU GAG GAG AAG UCU GCC GUU ACU – 3’
2. 5’ – AUG GUG CAC CUG ACU CCU GAG GAG AAG UCU GCC GUU ACU – 3’
a. PROTEIN
b. 5’ - MET VAL HIS LEU THR PRO GLU GLU LYS SER ALA VAL THR – 3’
3. 3’ – TAC CAC GTG GAC TGA GGA CAC CTC TTC AGA CGG CAA TGA – 5’
a. MRNA
b. 5’ - AUG GUG CAC CUG ACU CCU GUG GAG AAG UCU GCC GUU ACU – 3’
4. 5’ – AUG GUG CAC CUG ACU CCU GUG GAG AAG UCU GCC GUU ACU – 3’
a. PROTEIN
b. 5’ - MET VAL HIS LEU THR PRO VAL GLU LYS SER ALA VAL THR – 3’
Answer is there in the question, I answered again for cross checking it. I hope it serves the purpose.
Template DNA = 3’ – TAC CAC GTG GAC TGA GGA CTC CTC TTC AGA CGG CAA TGA – 5’
mRNA = 5' - AUG GUG CAC CUG ACU CCU GAG GAG AAG UCU GCC GUU ACU- 3'
Protein= Met Val His Leu Thr Pro Glu Glu Lys Ser Ala Val Thr
Template DNA= 3’ – TAC CAC GTG GAC TGA GGA CAC CTC TTC AGA CGG CAA TGA – 5’
mRNA=5'- AUG GUG CAC CUG ACU CCU GUG GAG AAG UCU GCC GUU ACU - 3'
PROTEIN= Met Val His Leu Thr Pro Val Glu Lys Ser Ala Val Thr
Transcribe the following DNA 1. 3’ – TAC CAC GTG GAC TGA GGA CTC CTC TTC...
Given the following transcripts: 1.) 5' - AUG GUG CAC CUG ACU CCU GAG GAG AAG UCU GCC GUU ACU -3' 2.) 5' - AUG GUG CAC CUG ACU CCU GUG GAG AAG UCU GCC GUU ACU - 3' I need to determine what difference exist between the two transcripts. How is GAG in transcript #1 different then GUG in transcript #2? What does this mean? Thank you!
The next DNA sequence is the MATRICE strand of a small gene. What is the complete amino acid sequence of the encoded peptide? GTCATGGCAACATAG 5'-3 Standard Genetic Code First position (5'end) U Second position UAU Tyr UAC Tyr UCA Ser UAA StopUGA Stop UAG Stop UUU Phe UUC Phe UUA Leu UUG Leu UGU Cys UGC Cys UCU Ser UCC Ser UCG Ser UGG Trp CUU Leu CUC Leu CUA Leu CUG Leu CCU Pro CCC Pro CCA Pr CCG...
15. Transcribe into mRNA and then translate into amino acids (protein) the following DNA sequence TAC ATG TCT AGG ATC. Write out the tRNA anticodons for each of the 5 codons as well. What is the complementary DNA sequence for the above DNA (the complementary sequence would be produced in DNA replication)? Suggested Format: DNA: TAC ATG TCT AGG ATC. Complementary: mRNA based on DNA: TRNAs that would pair with mRNA (the anticodon): Amino Acid Sequence: To transcribe the sequence...
If the sequence of an mRNA molecule is: 5' AUG GGA UUU CGA 3' (a) Give the sequence of the template strand of DNA. (Please indicate where the 5' and 3" ends are located) (1.5 marks) (b) Give the sequence of the non-template strand of DNA. (Please indicate where the 5' and 3" ends are located) (1.5 marks) (c) Give the amino acid sequence. (1.5 marks) You will require the following genetic code to answer this question. Second letter с...
Bring this DNA sequence to protein using the transcription
(3pts) and translation (4 pts) processes.
note: Pending the direction your DNA is located
Second position UUU Ae UCU UCC cys DU Sey UAU UAC UAA UAG UGU UGC UGA UGG UUA tyr Stop Stop JC Stop CUU CUC his CUA 5 'ATGCCGACGCCATAA 3' Lleve esta secuencia de ADN hasta proteína mediante los procesos de transcripción (3pts) y traducción (4 pts). First position (5'-end) CUC AUU AUC ile AUA AUG met...
A template strand of DNA in a gene reads 3’ CCA AGC TCT 5’.
Using the codon chart provided, answer the following
questions:
-What is the sequence of amino acids that is produced when this
gene is translated?
-If a mutation causes a substitution (an A instead of a T) 3’
CCA AGC ACT 5’, what effect will it have on the mRNA transcript AND
on the protein?
-What do we call this type of mutation?
Second letter U С...
A single mutation has occurred in the following DNA sequence. 5' ATG AAA TTA CCA 3' wild-type (normal) sequence 5' ATG AAG TTA CCA 3' mutant sequence (a) Identify and classify the mutation according to its molecular structure (i.e., insertion, deletion base substitution (transversion), or base substitution (transition)). Briefly explain why you selected this classification (1.75 marks) (b) Identify and classify the mutation according to its functional effects (i.e., frameshift, missense, nonsense, or silent). Briefly explain why you selected this...
You are synthesizing messenger RNAs in vitro with bases incorporated in random sequences with the ratio of 16:3A. What is the probability of obtaining a glycine (gly) codon? second base U UAU tyr DỤC phe UUA leu UACS UAA Stop UAG Stop G UGU UGC ſys UGA Stop UGG trp CGU CGC CAU , his CÁC his CỦA / leu CAA 1. arg CGA с UUU 2 UCU UCC ser UCA UUG) UCG CUU CCU CUC CCC CCA } pro...
18 please
18a. The DNA is mutated on the 4th nucleotide (see bases in box) to the follo DNA :3TAC GCT GAG AGA GAC ACTS sº ATG CGA CTC TCT CTG TGA 3» 18b. (2pts) Does this mutation change the amino acid sequence? If yes - what is 18c. (2pts) Can this mutation change the way the protein functions? 18d. (2pts) How can a DNA mutation change protein function? Explain your answer in terms of gene expression. 15. Answer the...
Use the genetic code table to answer the following question: Second Base First Base Third Base UUU UUC Phenylalanine U UCU UAC UCA UCG Serine UUA UUG Leucine UAU UGU UAC Tyrosine UGC Cysteine UAA Stop codon UGA Stop codon UAG Stop codon UGG Tryptophan CAU CGU Histidine CAC CGC Arginine CAG Glutamine CGG CUU CUC CUA CUG Leucine CCU CCC CCA CCG Proline CAA CGA AUU AAU Asparagine AGU Serine AGC AUC AUA Isolaucine ACU ACC ACA ACG AAC...