Question

c++ program

Create a file sales.cpp. to:

·Write a function int lastNeg(vector<float> diffs)to return the index of the last negative value in the vector. Return -1 if there are no negative values.

·Write main() to ask the user to enter sales numbers

·Starting with the 2^nd value, compute the difference from the previous value and store this difference into a vector<float>

·Call lastNeg() to see when the most recent drop occurred

·Output when the last drop in sales occurred, or “no drops in sales”

·Two sample runs: (^Z is for Windows end of input)

Simple sales analysis

Enter sales numbers, at least two, separated by whitespace

3 2 8 6 7

^Z

last drop occurred 1 days ago

________________________________________

Simple sales analysis

Enter sales numbers, at least two, separated by whitespace

1 2.5

^Z

no drops in sales

Answer 1

`Hey,

Note: Brother if you have any queries related the answer please do comment. I would be very happy to resolve all your queries.

#include <iostream>
#include<vector>
using namespace std;
int lastNeg(vector<float> diffs)
{
for(int i=diffs.size()-1;i>=0;i--)
{
if(diffs[i]<0)
return i;
}
return -1;
}
int main()
{
cout<<"Enter sales numbers, at least two, separated by whitespace\n";
vector<float> v1,diffs;
float num;
while(cin>>num)
{
v1.push_back(num);
}
for(int i=1;i<v1.size();i++)
{
diffs.push_back(v1[i]-v1[i-1]);
}
int ind=lastNeg(diffs);
if(ind!=-1)
cout<<"last drop occurred "<<(diffs.size()-ind-1)<<" days ago\n";
else
{
cout<<"no drops in sales\n";
}
return 0;
}

Kindly revert for any queries

Thanks.