Which is NOT a necessary requirement for a proper reaction mechanism?
A) The rate-determining step must be the first step
B) An elementary step may be unimolecular
C) The sum of elementary steps must equal the net balanced chemical equation
D) An intermediate must be produced in an early step and consumed in a later step
A) The rate-determining step must be the first step - is not a necessary requirement for a proper reaction mechanism.
this can be explained by the rate of a different reaction. The slowest reaction step where a higher amount of energy is required is the rate-determining step. This measure may be Step-1 or step-2 or any other step not necessary to be step-1.
There are many reactions where the first step is the reversible reaction and second or third step are the slowest steps so this slowest step must be the rate-determining step.
Which is NOT a necessary requirement for a proper reaction mechanism? A) The rate-determining step must...
What two criteria must a plausible mechanism meet? Select both criteria in the options. elementary steps must sum to the net reaction the mechanism must include at least two intermediates the slow step must always be the first step in the mechanism the rate law of the net reaction must match the rate law of the slowest step the mechanism must involve at least one catalyst Areaction profile is shown. Which step is the rate limiting (or rate determining) step...
Which statement below concerning elementary processes (or
steps), the mechanism of a reaction and the overall reaction is
correct?
The overall rate law derived from the mechanism must agree with
the observed rate law for the overall reaction.
The rate law for an elementary process can be predicted from
the chemical equation for that process.
The rate law for the rate determining step is directly related
to the rate law for the overall reaction.
All the above statements are either...
Suppose the reaction between nitric oxide and oxygen proceeds by the following mechanism: rate constant elementary reaction step NO(g)+ 02(g) NO2(9) 0(g) 1 NO(g) O(g) NO2(9) k2 2 Suppose also k,»k,. That is, the first step is much faster than the second. 2* Write the balanced chemical equation for the overall chemical reaction: Write the experimentally observable rate law for the overall chemical reaction rate k Note: your answer should not contain the concentrations of any intermediates. Express the rate...
Which statement is false concerning elementary steps in a reaction mechanism? the rate law can be deduced from the stoichiometry of reactants for an elementary step the overall molecularity for an elementary step is the sum of the stoichiometric coefficients for all reactants in that step the rate law for an elementary step must be determined experimentally the rate law for the overall reaction is always the same as the rate law for the slowest elementary step both (c) and...
Suppose the synthesis of ethylene dichloride proceeds by the following mechanism: step rate constant elementary reaction CH,CH, (g)+ci, (g) → CH,CH,ci* (g)+ciº (9) CH,CH,CI* (g)+C1 (g) → CH,CH,C1, (g) Suppose also kq «k2. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction. Write the experimentally- observable rate law for the overall chemical reaction. Note: your answer should not contain the concentrations of any intermediates. rate = % 0
To understand how elementary steps make up a mechanism and how the rate law for an elementary step can be determined. Very often, a reaction does not tell us the whole story. For instance, the reaction NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) does not involve a collision between an NO2NO2 molecule and a COCO molecule. Based on experimental data at moderate temperatures, this reaction is thought to occur in the following two steps: NO2(g)+NO2(g)→NO3(g)+NO(g)NO2(g)+NO2(g)→NO3(g)+NO(g) NO3(g)+CO(g)→CO2(g)+NO2(g)NO3(g)+CO(g)→CO2(g)+NO2(g) Each individual step is called an elementary step. Together, these...
step Suppose the reaction between nitric oxide and oxygen proceeds by the following mechanism: elementary reaction rate constant NO(g) +0,() ► NO,()+(2) ky 2 NO(g) +0 (2) NOG) kz Suppose also , ekz. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction. Write the experimentally observable rate law for the overall chemical reaction. Note: your answer should not contain the concentrations of any intermediates x 5 ?
— O KINETICS AND EQUILIBRIUM Writing the rate law implied by a simple mechanism Suppose the formation of nitrosyl chloride proceeds by the following mechanism: step elementary reaction rate constant 1 NO(g) + Cl2(9) ► NOCI (9) km 2 NOCI (9) + NO(g) → 2 NOCI (9) kz Suppose also k«k. That is, the first slower than the second 0-0 Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical...
8. In a reaction mechanism, a substance that is produced in one step, and consumed in a later step is a(n): Intermediate. Tranistion state. Catalyst. Starting material. 9. A substance that is present before and after the reaction takes place, and may increase the reaction rate by changing its mechanism is a(n): Catalyst. Intermediate. Starting material. Product. 12. An intermediate in an acid-catalyzed esterification has a partial _____ charge at its tetrahedral carbon center. positive negative 13. Water acts as...
Which of the following statements about an elementary process or step is/are correct? 1) Intermediates in a reaction cannot be involved in the rate determining step ii) In the rate equation for the forward reaction of an elementary step, the overall reaction order is equal to the number of reactant molecules in the step iii) To be the rate determining step in a mechanism, an elementary step must be exothermic O A. ii and ill only B. i and iii...