Calculating theoretical yield Balanced equation of reaction: 2 Al(NO3)3 (s) + 3 K2CO3 (aq) = 6...
Calculating theoretical yield
Balanced equation of reaction: 2 Al(NO3)3 (s) + 3 K2CO3 (aq) = 6 KNO3(aq) + Al2(CO3)3 (s)
(A)
If you combine 32.4mL of a 1.23M Al(NO3)3 solution of with 25.6mL of a 1.67M K2CO3 solution what is the maximum yield in of aluminum carbonate (in grams) you can get? (Show all work)
(B)
If you combine 24.13g Al(NO3)3 with 25.6 mL of a 0.167M K2CO3 solution what is the maximum yield of aluminum carbonate (in grams) you can get? (Show all work)
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Calculating theoretical yield
Balanced equation of
reaction: 2
Al(NO3)3 (s) + 3
K2CO3 (aq) = 6...
3. Ca(NO3)2(aq) + K2CO3(aq) --> CaCO3(s) + 2 KNO3(aq) 50 mL of 1.000 M Ca(NO3)2 was...
3. Ca(NO3)2(aq) + K2CO3(aq) --> CaCO3(s) + 2 KNO3(aq) 50 mL of 1.000 M Ca(NO3)2 was reacted with excess potassium carbonate. What mass of calcium carbonate will be made? Repeat your answer to two sig figs and omit the unit label.
1. Zinc nitrate reacts with potassium phosphate to form the insoluble compound, zinc phosphate. The reaction...
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If 2.50 g of aluminum nitrate (Al(NO3)3) reacts to form 1.83 g of solid aluminum sulfate,...
If 2.50 g of aluminum nitrate (Al(NO3)3) reacts to form 1.83 g of solid aluminum sulfate, what is the percent yield? 2Al(NO3)3(aq) + 3(NH4)2SO4(aq) → Al2(SO4)3(s) + 6NH4NO3(aq)
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Sulfuric acid (H2SO4) dissolves Aluminum metal according to the reaction: 2 Al(s)+ 3 H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g) Suppose you want to dissolve an Aluminum block with a mass of 15.2 g. What minimum mass of H2SO4 (in g) do you need? What mass of H2 gas (in g) can the complete reaction of the aluminum block produce? Please Show Work
3Cu(NO3)2(aq) + 2Al(s) ---> 3Cu(s) + 2Al(NO3)3(aq) if you have 32 moles of aluminum, what is...
3Cu(NO3)2(aq) + 2Al(s) ---> 3Cu(s) + 2Al(NO3)3(aq) if you have 32 moles of aluminum, what is the maximum number of grams of copper that you can form?
23. Lead (II) bromide is prepared using the following reaction: Pb(NO3)2 (aq) + KBr (aq) →...
23. Lead (II) bromide is prepared using the following reaction: Pb(NO3)2 (aq) + KBr (aq) → PbBra(s) + KNO3(aq) (unbalanced) How many milliliters of 1.5M Lead (II) nitrate Pb (NO3), are needed to prepare 150 grams of PbBr2 in excess potassium bromide solution. Assume you have 100% yield. Fill in the stoichiometric pathway for this problem: (2 points) Show the dimensional analysis calculation required for this problem: (3 points)
Select the Redox Reactions: A) Mg + 2H+--> Mg2+ +H2(g) B) K2CO3(aq) + Sr(NO3)2(aq)--> SrCO3(s) +...
Select the Redox Reactions: A) Mg + 2H+--> Mg2+ +H2(g) B) K2CO3(aq) + Sr(NO3)2(aq)--> SrCO3(s) + 2KNO3(aq) C) 2OH- + 2ClO-2 --> ClO2- + ClO3- + H2O D) H+ + OH- --> H2O E) KSCN (aq) + Fe(NO3)3(aq) --> FeSCN2+(aq) + KNO3 (aq) + 2NO3- (aq) F) AgCl(s) +2NH3(aq) --> Ag(NH3)2+ (aq) +Cl- (aq)
Consider the following balanced equation: 3Li2S(aq) + 2Bi(NO3)3(aq) → 6LiNO3(aq) + Bi2S3(s) If 27.1 moles of...
Consider the following balanced equation: 3Li2S(aq) + 2Bi(NO3)3(aq) → 6LiNO3(aq) + Bi2S3(s) If 27.1 moles of Li2S(aq) and 27.0 moles of Bi(NO3)3(aq) are allowed to react, what is the theoretical yield of LiNO3(aq)?
Consider the following precipitation reaction: 2 K3PO4 (aq) + 3 Co(NO3)2 (aq) ? Co3(PO4)2 (s) +...
Consider the following precipitation reaction: 2 K3PO4 (aq) + 3 Co(NO3)2 (aq) ? Co3(PO4)2 (s) + 6 KNO3 (aq) What volume of 0.222 M K3PO4 (aq) in milliliters is needed to react with 36.75 mL of 0.250 M Co(NO3)2 (aq)? NG 5 6. Consider the following precipitation reaction: 5 Fe2+(aq) + MnO4-(aq) + 8 H+(aq) ? 5 Fe3+(aq) + Mn2+(aq) + 4 H2O(l) An iron sample weighing 0.214 g is converted into Fe2+(aq) and requires 31.57 mL of MnO4-(aq) according...
Copper(II) ions can be displaced by aluminum metal. 3 CuSO4(aq) + 2 Al(s) → Al2(SO4)3(aq) +...
Copper(II) ions can be displaced by aluminum metal. 3 CuSO4(aq) + 2 Al(s) → Al2(SO4)3(aq) + 3 Cu(s) How many grams of Al would be needed to displace all of the copper ions in 40.5 mL of 0.420 M CuSO4? How many grams of Cu would be recovered from the copper ions in 40.5 mL of 0.420 M CuSO4?
23. Lead (II) bromide is prepared using the following reaction: Pb(NO3)2 (aq) + KBr (aq) → PbBra(s) + KNO3(aq) (unbalanced) How many milliliters of 1.5M Lead (II) nitrate Pb (NO3), are needed to prepare 150 grams of PbBr2 in excess potassium bromide solution. Assume you have 100% yield. Fill in the stoichiometric pathway for this problem: (2 points) Show the dimensional analysis calculation required for this problem: (3 points)
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