calculate the probability of the production of the aaBbccddEeFF and AaBbCcddEeFf genotypes for the following cross:
AaBbccddEeFf x AaBbCcddeeFf
MY TEACHERS ANSWER: 1/4096
I don't believe my teachers answer is correct.
AaBbccddEeFf x AaBbCcddeeFf
let`s divide this into 6 different crosses
Aa * Aa
| A | a | |
| A | AA | Aa |
| a | Aa | aa |
probability of getting Aa=number of Aa/total number=2/4=1/2
probability of getting aa= number of aa/total number=1/4
Bb * Bb
| B | b | |
| B | BB | Bb |
| b | Bb | bb |
probability of getting Bb= number of Bb/total number=2/4=1/2
Cc * cc
| C | c | |
| c | Cc | cc |
| c | Cc | cc |
probability of getting Cc= number of Cc/total number=2/4=1/2
probability of getting cc= number of cc/total number=2/4=1/2
dd* dd
dd
all the progenies are dd
probability of getting dd=1
Ee * ee
| E | e | |
| e | Ee | ee |
| e | Ee | ee |
probability of getting Ee= number of Ee/total number=2/4=1/2
Ff * Ff
| F | f | |
| F | FF | Ff |
| f | Ff | ff |
probability of getting Ff= number of Ff/total number=2/4=1/2
probability of getting FF= number of FF/total number=1/4
probability of getting aaBbccddEeFF = probability of
getting aa
probability of getting Bb
probability of getting cc
probability of getting dd
probability of getting Ee
probability of getting FF= 1/4
1/2
1/2
1
1/2
1/4=1/128
probability of getting AaBbCcddEeFf = probability of getting Aa
probability of getting Bb
probability of getting Cc
probability of getting dd
probability of getting Ee
probability of getting Ff= 1/2
1/2
1/2
1
1/2
1/2=1/32
probability of getting aaBbccddEeFF and AaBbCcddEeFf=probability
of getting aaBbccddEeFF
probability
of getting AaBbCcddEeF=1/128
1/32=1/4096
so the answer is 1/4096
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