MIPS assembler language Generate an instruction sequence that will result in an arithmetic overflow. Do not...
MIPS assembler language
Generate an instruction sequence that will result in an arithmetic overflow. Do not use a loop, but rather create a specific code sequence.
Homework Answers
Solution:----------
MIPS integers are 32-bit, and since you'll be using signed integers, the maximum value is 231-1 ( 2147483647 or hex 7FFFFFFF). Thus any addition which results in a number larger than this should throw an exception, e.g if you try to add 1 to 2147483647:
# Load 2147483647 into $s1
LUI $s0, 32767
ORI $s1, $s0, 65535
# Add 1 to $s1 and store in $s2. This should produce an
arithmetic overflow .
ADDI $s2, $s1, 1
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MIPS assembler language
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