de Broglie Matter waves and the non-relativistic electron: The Double slit experiment for electrons
(a) Electrons were accelerated through a potential difference of V = 50 kV. Is it permissible to use non- relativistic expressions to find the linear momentum of the electrons? Calculate the de Broglie wavelength of an electron in the Hitachi experiment
(b) The spacing between the fringes observed was 90 nm. [The image shown in Fig 1.4 in the textbook has been magnified further of course, to generate fringes on the imaging detector that were separated by about 1.4 mm.] Given the 90 nm fringe spacing, what is the spacing between the two slits?
(c) The distance to the screen was about 1.5 m, while the average spacing between two electrons was 150 km long, effectively ruling out the chances of two electrons being in the apparatus at the same time. Can you estimate how long it would have taken for the entire measurement of 160000 electrons?
[Note: The length of the electron wavepacket was about 1 micron. You will learn in Chapter 2 what this means, and why this is important in ruling out the presence of two electrons at the same time being in the double-slit apparatus].
Estimate time interval between the launch of two successive electrons, knowing an estimate of their speeds.
PLEASE DO PART C ONLY
The electrons are charged particles and have a magnetic field associated with it. If two electrons are inside the slit at the same time, they wil cause interaction with one another. Also, the experiment demonstrated here is used to demonstrate the probabilistic nature of quantum particles.
The potential used to accelerate the electrons is
V = 50 kV
So, the energy of the electrons is
(kilo
electron volt)
Using non relativistic equations,

The velocity of electron is given by


Since the distance between the two electrons is 150 km = 150000 m,
The time between two electrons is
t = distance/speed = 150000/(1.325*10^8) = 0.0011321 s
The entire measurement consists of 160000 electrons.
The time taken for this many electrons to reach the screen is
T = 160000*0.0011321 = 181.132 s
de Broglie Matter waves and the non-relativistic electron: The Double slit experiment for electrons (a) Electrons...
A double-slit interference experiment is performed with two very narrow slits separated by 0.19 mm. The experiment uses red light with a wavelength of 700 nm and projects the interference pattern onto a screen 5.0 m away from the slits. (a) What is the distance between two nearby bright fringes on the screen? (b) What is the distance between two nearby dark fringes on the screen? Assume these fringes are all near θ = 0. A Young's double-slit interference experiment...
A double-slit experiment with electrons is arranged so that the electron source emits only one electron, and only after the previously emitted electron has been already detected, after passing through the double-slit screen. In that way, only one electron may be present in the experimental setup, anywhere between the electron source and the electron detection surface. The experiment is repeated a million times. Which of the following is correct: a. The interference pattern will be observed already for each individual...
Matter Waves - Double Slit Interference Previously we learned the wave behaviors of light - the single-slit diffraction, and the double-slit interference. In this problem, you will explore the wave behaviors of matter (particles). Double Slit Screen Interference y=Ltane 0 L bright fringes: sine Dark fringes above central sin 8 = (m m-0, 11, 12(constructive) (destructive). Matter Waves - Double Slit electrons Max Men Max photons Electrons pass through a double slit separated by d = 0.0100 um, 1um =...
In a double-slit experiment the distance between slits is d = 4 mm and the distance to the screen is 1.4 m. There are two interference patterns on the screen: one due to light with λ1=470 nm and another due light with λ2=610 nm. What is the separation between third order (m = 3) bright fringes of the two patterns?
5. A double slit experiment with d=0.025 mm uses 600 nm light. What is the spacing between adjacent bright fringes on a screen 75 cm away?
A Young’s double-slit apparatus is set up so that a screen is positioned 2.1 m from the double slits, and the spacing between the two slits is 0.033 mm. What is the distance between alternating bright fringes on the screen if the light source has a wavelength of 678 nm? (1 nm = 10 −9 m)
Assume that the double-slit experiment could be carried out with electrons using a slit spacing of bb = 10.0 nmnm. To be able to observe diffraction, we choose λλ = bb, and because diffraction requires reasonably monochromatic radiation, we choose Δp/pΔp/p = 0.0100. part A What electron momentum would give a position uncertainty of 2.59×10−10 mm ? part B What is the ratio of the wavelength and the slit spacing for this momentum?
In a Young’s double-slit experiment that uses electrons, the angle that locates the first-order bright fringes is θA = 9.0 × 10-4 degrees when the magnitude of the electron momentum is pA = 1.2 × 10-22 kg*m/s. With the same double slit, what momentum magnitude pB is necessary so that an angle of θB = 18.0 × 10-4 degrees locates the first-order bright fringes?
Question 4 5 pts A double-slit experiment has a slit-separation distance of 0.04 mm and a slit-to-screen distance of 75 cm. If a green laser operating at 532 nm wavelength shines light on the slits, what will be the spacing on the screen between adjacent bright fringes? 5 mm O 10 mm O 15 mm O 25 mm O 50 mm o
Question 4 5 pts A double-slit experiment has a slit-separation distance of 0.04 mm and a slit-to-screen distance of 75 cm. If a green laser operating at 532 nm wavelength shines light on the slits, what will be the spacing on the screen between adjacent bright fringes? O 5 mm O 10 mm 15 mm O 25 mm O 50 mm