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If you change the structure of a small molecule, and the ΔG° of protonation of the...

If you change the structure of a small molecule, and the ΔG° of protonation of the molecule changes by -2.94 kcal/mol, what happens to the pKA?

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Answer #1

-2.94 kcal into joules

= -12301 joules

= ∆G° = - R*T*ln K

= -12301 = -8.314*298*ln(Ka)

= 143.300

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