The meter stick is in static equilibrium so the net force on it is zero.
T1 + T2 = Mg ==> 627+455 = M x 9.81 ==> M=110.29 kg
(b) Equating the torque
about point A
Ta=Mgx-T2 x l =0
l=38-12=26 cm = 0.26 m
110.29 x 9.81 x ? = 455 x 0.26 ==> ? = 0.109 m = 10.9 cm
so the position of mass = 10.9 + 12 = 22.9 cm
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