% Ionization using Henderson Hasselbalch equation ionization given ph and pka: pka:8.0 at a pH of...

Question

Question

% Ionization using Henderson Hasselbalch equation ionization given ph and pka:

pka:8.0

at a pH of 7.4 what is the percent ionization?

Here is what I have so far:

pka=pH + log(acid/base)

8.0=7.4+ log (acid/base)

0.6= log (acid/base)

10^0.6= (acid/base) = 3.98

this is where I got stuck. my solution should be 80% but I not sure how. please show all work.

Book answer: % acid form = (3.98 x100)/ 4.98 = 79.99 %

Where did they get 4.98???

science chemistry

Answer 1

Answer #1

Answer 2

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