A long solenoid has a length of 0.65m and contains 1400 turns of a wire. There is a current of 4.7A in the wire. What is the magnitude of the magnetic field within the solenoid?
The Magnitude of uniform magnetic field inside the solenoid, B =
where
=
4π(10^-7)
n= number of turns per unit length= N/L
I = current flowing
Given n=1400/0.65= 2153.84 m^-1
I = 4.7 A
Therefore B= 4π (10^-7)* (2153.84)* 4.7= 1.27 x (10^-2) Tesla
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