Question

Problem 2-

The three charges are at the three vertices of an equilateral triangle. (All angles are 60degrees), Equilateral side of the triangle = 10 cm =0.10 m

q _{1 =}   + 3.0 µC

q ₂ = +3 .0 µC

q _{3 =} -6.0 µC

1 µC = 10^-6

a. Calculate the force acting on on q ₂ by q ₁ . Name this force F_{2 .}

Show formula and calculation here:

b) Calculate the force acting on q ₂ by q ₃ . Name this force F_{3 .}

Show formula and calculation here:

c)Draw the force acting on q ₂ by q ₁ on the figure .   Label this force F₁

Hint: To better understand the question, I showed this force on the figure

b) Find the components of force F₁   on X and Y-axes.

F_1X =

F_1Y =

d) Draw the force acting on q ₂   by q ₃ on the figure.   Label this force F₃

d) Find the components of force F₃   on X and Y-axes.

F_{3 X} =

F_{3 Y} =

e) Find the net force in X-direction.

F_{net X} =

f) Find the net force in Y-direction

F_{net Y} =

g) Use Pythagorean Theorem to find the resultant force.

h) Use tangent to find the direction (angle) the resultant makes with horizontal.

Answer 1