The internal energy change (ΔEsys) for a system is -65.0 kJ when it gives off 45.0...

Question

Question

The internal energy change (ΔE_sys) for a system is -65.0 kJ when it gives off 45.0 kJ

Of heat. How much work has to be done in the process?

science chemistry

Answer 1

Answer #1

According to First law of thermodynamics,

Change in internal energy, E = Q + W

where Q is the energy absorbed by the system

W is the work done on system

Given : E = -65.0 kJ

Q = -45.0 kJ

W = E - Q

W = (-65.0 kJ) - (-45.0 kJ)

W = -65.0 kJ + 45.0 kJ

W = -20.0 kJ (negative sign indicates work is done by the system)

Work done in the process = 20.0 kJ

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Answer 2

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