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Four grams of O2 gas (molecular weight 32 g/mol) is compressed from an initial state of...

Four grams of O2 gas (molecular weight 32 g/mol) is compressed from an initial state of Pi = 1.30×105Pa, Vi = 4.50 L to a final state of Pf = 1.10×105 Pa, Vf =1.9 L along a path that forms a straight line on a PV diagram.

(a) What is the final temperature?

(b) What is the work done on the gas?

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Answer #1

(a) n = 4 / 32 = 0.125

using

PV = nRT

T = PV / nR

T = 110 * 1.9 / 0.125 * 8.3145

T = 201.1 K

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(b) work done = area under the curve

area comprises of a triangle and a rectangle

Work = 1/2 * 2.6e-3 * 20000 + 1.1e5 * 2.6e-3

Work = 312 J

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