Let random variable X follow a triangular distribution with lower bound a = 0, most likely value m = 9.2, and upper bound b = 16.
Find P(X > 3.0).
Round your answer to three decimal places of accuracy.
Solution :
Given that,
a = 0
b = 16
P(x > c) = (b - c) / (b - a)
P(x >3.0 ) = (16 - 3.0) / (16 - 0 )
= 13 / 16
= 0.812
Let random variable X follow a triangular distribution with lower bound a = 0, most likely...
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