QUESTION 19
For the equilibrium 2PH3(g) ⇌ P2(g) +3H2(g), the equilibrium partial pressures are PPH3=0.029 atm, PP2=0.699 atm, and PH2=0.557 atm at 738K.
Calculate Kp.
*Please report 3 significant figures. Numbers only, No unit. No scientific notation.
QUESTION 19 For the equilibrium 2PH3(g) ⇌ P2(g) +3H2(g), the equilibrium partial pressures are PPH3=0.029 atm,...
For the equilibrium 2PH3(g) ⇌ P2(g) +3H2(g), the equilibrium partial pressures are PPH3=0.049 atm, PP2=0.498 atm, and PH2=0.776 atm at 738K. Calculate Kp.
help please stressing
QUESTION 2 For the equilibrium 2PH3(e) = P2(8) +3H2(8), the equilibrium partial pressures are Ppzz-0.023 atm, Pp,-0.321 atm, and PH, -0.732 atm at 738K. Calculate Kp. *Please report 3 significant figures. Numbers only, No unit. No scientific notation. QUESTION 3 CH4(g) + 2 O2(g) = CO2(g) + 2 H2O(1) AH° -- 890 kJ Raising the temperature will result in shift the equilibrium to the right shift the equilibrium to the left O more information is needed Keq...
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CaCO3(s) = CaO (s) + CO2 (g) At 658 °C, the reaction reaches equilibrium. If PcO2 =2.17 atm, what is Kc value ? *Please report 3 significant figures. Numbers only, No unit. No scientific notation. The slope and intercept of an Arrhenius plot made for the first-order decomposition reaction are -7865.2 K and 26.098 at 303K, what is the value of the activation energy (KJ/mol) at this temperature? *Please report 3 significant figures. Numbers only, no unit....
Phosphine (PH3) decomposes at elevated temperatures, yielding gaseous P2 and H2: 2PH3(g)⇌P2(g)+3H2(g) Kp= 398 at 873 K When a mixture of PH3, P2, and H2 comes to equilibrium at 873 K, PP2= 0.422 atm and PH2= 0.822 atm. What is PPH3?
HQ14.35 Unanswered The reaction mixture N2(g) +3H2(g)2NH3(g) has the following equilibrium partial pressures: PN2- 2.40 atm, PH2-1.60 atm, and PNH3 22.10 atm. Calculate the equilibrium constant Kp. Report your answer to the correct number of significant figures. Type your response
can someone please help me with these three please
QUESTION 1 The rate law of a reaction is rate = k[X][Y][Z]. The units of the rate constant are O mol2 L-25-1 OL2 mol-25-1 mol L-lg-2 O L mol-lg-1 O mol L-15-1 QUESTION 2 For the equilibrium 2PH3(e) = P2(e)+3H2(g), the equilibrium partial pressures are PpH, -0.023 atm, PP, 0.32latm. and PH -0.732 atm at 738K. Calculate Kp. *Please report 3 significant figures. Numbers only, No unit. No scientific notation. QUESTION...
Calculate the partial pressure (in atm) of CH3OH at equilibrium when 2.74 atm of CH3I and 7.27 atm of H2O react at 3000 K according to the following chemical equation: CH3I (g) + H2O (g) ⇌ CH3OH (g) + HI (g) Kp = 7.30 Report your answer to three significant figures in scientific notation.
Calculate the partial pressure (in atm) of HBr at equilibrium when 4.05 atm of C2H6 and 4.05 atm of Br2 react at 2500 K according to the following chemical equation: C2H6 (g) + Br2 (g) ⇌ C2H5Br (g) + HBr (g) Kp = 2.82×101 Report your answer to three significant figures in scientific notation.
Calculate the partial pressure (in atm) of HBr at equilibrium when 3.16 atm of CH3Br and 6.55 atm of H2O react at 1000 K according to the following chemical equation: CH3Br (g) + H2O (g) ⇌ CH3OH (g) + HBr (g) Kp = 6.66×10-2 Report your answer to three significant figures in scientific notation.
Calculate the partial pressure (in atm) of S2 at equilibrium when 2.61 atm of H2S dissociates at 600 K according to the following chemical equilbrium: 2H2S(g) ⇌ 2H2(g) + S2(g) Kp = 2.53×10-11 If the 5% approximation is valid, use the assumption to compute the partial pressure. Report your answer to three significant figures in scientific notation.