You have a solution that is a mixture of two compounds, A and B. The molar...
You have a solution that is a mixture of two compounds, A and B. The molar extinction coefficient (e) of substance A at 260nm and 280nm is 5248 and 3150 respectively. Compound B has a molar extinction coefficient of 311 and 350 at 260 nm and 280 nm rspectively. You determine that the solution has an absorbance of 0.83 at 260 nm and 0.67 at 280 nm. Can the individual concentrations of A and B be calculated from these data? If so, what are the concnetrations of each compound in this solution?
Someone else answered with:
@ 260 nm
A = (5248 x [A]) + (311 x [B]) = 0.83
@ 280 nm
A =(3150 x [A]) + (350 x [B]) = 0.67
[A] = 0.000095817
[B] = 0.00105193
While those are the correct answers, i'm not sure how they were gotten. How do you relate the two equations to find those values?
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