Question

For each two carbon fragment that is removed in beta oxidation, 1 FADH2 and 1 NADH + H+ are produced. Each FADH2 can produce two ATP, and each NADH can produce 3 ATP. Each two carbon fragment enters the Kreb's cycle. If you were to completely metabolize a 14 carbon fatty acid by beta oxidation, you would get 6 FADH2 and 6 NADH + 6H+ from beta oxidation, and you would have 7 acetyl CoA molecules that would enter the Kreb's cycle. How many ATP would be produced (between beta oxidation and Kreb's cycle redox reactions) -- and don't forget the substrate level phosphorylation that takes place in the Kreb's cycle?

Answer 1

Every acetyl-CoA yields 3 NADH + 1 FADH2 + 1 ATP during Krebs cycle giving total 12 ATP.

So total 7 acetyl CoA gives 7 X 12 = 84 ATPs.

6 FADH2 gives 12 ATPs

6 NADH gives 18 ATPs

so total of 114 ATPs.