Question

Calculate the net number of moles of ATP generated from the oxidation of 1 mole of decanoic acid if all of the NADH, FADH2, and acetyl-CoA are metabolized by citrate cycle and oxidative phosphorylation.

a) There are 100 net moles of ATP generated

b) There are 64 net moles of ATP generated

c) There are 106 net moles of ATP generated

d) There are 148 net moles of ATP generated

The correct answer is B. The question is if you could explain how you get 64 moles?

Answer 1

= 4 = 1647 Decandic acid - cio H20 n = 10 (no. of c atama) No. of NADH = n | I Net ATP = 0 10+ 6+ 50 -& ATP from NADH = 4x4.5 = 66-2 (INAOH = 2:5 ATP) No. of FADHI = n - - ATP from NADH = 4 x 15 la FAOH = 1.5 ATP) No. of TCA ņ cylles ATP from TCA = 5x10- 50 CITCA = 10 ATP) ATP consumed per ③ exidation - 2 - fatty acid molecule

You can use this fatty acid balance sheet by any fatty acid, by replacing the value of n.

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