A 100 kg man stands up in a 50-kg boat of length 5m. He walks from a point 2 m from the right end to a point 1 m from the left end. If resistance to motion of the boat in the water can be neglected, how far does the boat move during the process? Please give steps!
Hi,
Hope you are doing well.
You can use a simple formula to solve these kind of problems. The center of mass shift or the distance boat moves is given by,

Where given that,
Mass of man, m=100 kg.
Mass of boat, M=50 kg.
Distance he travelled on boat, L=2m-1m=1m


A 100 kg man stands up in a 50-kg boat of length 5m. He walks from...
Problem
8.106
A 45.0-kg
woman stands up in a 60.0-kg
canoe 5.00
m long. She walks from a point 1.00
m from one end to a point 1.00
m from the other end (the figure (Figure 1) ).
Part A
If you ignore resistance to motion of the
canoe in the water, how far does the canoe move during this
process?
dcanoe =
m to the left
A 55.0 kg woman stands up in a 70.0 kg canoe of length 5.00 m . She walks from a point 1.00 m from one end to a point 1.00 m from the other end. If the resistance of the water is negligible, how far does the canoe move during this process?
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