Question

1) A weather balloon filled with He gas to a volume of 262 L on a day when the temperature was 18°C. The balloon was only released the next day when the temperature was -10°C. Calculate the new volume of the weather balloon. Assume that the atmospheric pressure remained the same on both days.

2) The volume of an empty flask with a one-holed stopper was 285 ml (V1). You heated the flask for 1 minute (T1) and then cooled it in a 22.0°C water reservoir (T2). A volume of 85.0 mL of water was drawn into the flask as the air in the flask cooled (V2 = V1-85.0mL).

a. What was the temperature of the hot air in the flask?

b. What is the value of Charles’ Law constant for the experiment above in question 2? k = V1/T1 (that's k = v1 over T1))

Answer 1

Ans 1 :

The volume of gas is related to the temperature (constant pressure) as :

V1 T2 = V2 T1

here V1 = 262 L

T1 = 18 C = 291.15 K

T2 = -10 C = 263.15 K

putting values :

262 L x 263.15 K = V2 x 291.15 K

V2 = 236.8 L

So the new volume of the balloon will be 236.8 L.