5. A 25 kg falling object strikes the ground with a speed of 12.5 m/s. If the kinetic energy of the object when it hits the ground is equal to the gravitational potential energy at some height above the ground, what is the height?
From energy conservation, final KE = initial PE
m v^2 /2 = m g h
h = v^2 / (2 g )
h = (12.5 m/s)^2 / (2 x 9.8 m/s^2)
h = 7.97 m
5. A 25 kg falling object strikes the ground with a speed of 12.5 m/s. If...
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