A voltage source of 10 V is connected to a series RC circuit where C=3.0μF and R= 2.0×10^6 Ω. Find the amount of time required for the capacitor to reach 95% of its maximum voltage.
Time constant, T = RC
T = 2 x 10^6 x 3 x 10^-6 = 6 sec
Charge, Q = Qo (1 - e^(-t/T))
0.95 = 1 - e^(-t/T)
t = - T ln(1 - 0.95)
t = - 6 ln(0.05)
t = 18 sec
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