A copper wire has a square cross section 2.1 mm on a side. The wire is 3.5 m long and carries a current of 3.6 A . The density of free electrons is 8.5×1028m−3
Question should be
Part A:
Find the magnitude of the current density in the wire.
Answer=
a)J = I/A
J = current density in amperes/m2
I = current through a conductor, in amperes
A = cross-sectional area of the conductor, m2
A=(2.1x10^-3)^2
A=4.41x10^-6 m^2
J=3.6A/4.41x10^-6 m^2
J=816326.53A/m^2
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