(10)
ES : earliest time and activity can start
EF : earliest start an activity time
LS : latest time an activity can cast without delaying critical path
LF : latest start and finish time
Relationships:
EF = ES + Dur - 1
ES = EF of prev (largest) + 1
LF = LS of succ (smallest) - 1
LS = LF - Dur + 1
Float = LS - ES = LF - EF
(11)
a = optimistic time estimates
m = most likely time estimate
b = Pessimistic time estimate
10. Explain the following, and their relationships: ES, EF, LS, LF 11. What are the three variabl...
Question 5 For the project depicted below, a) Compute the ES, EF, LS, and LF times for the network. b) Explain how the ES for Activity 3 is obtained. c) Explain how the LF time for Activity 1 is obtained. d) What is the critical path for the project? e) How long do you expect the project to take to complete? Activity 4 Activity 2 ES= EF= wks LSELF ES= EF T=5 wks LSELF= Activity 1 ES= EF= T=6 wks...
For the following Engineering project, draw the network diagram and calculate ES, EF, LS, LF, TF Predecessors Durations (Days) A1 3 A2 A1 7 A3 A1 14 A4 A2, A3 3 Activity ES EF LF LS TF A1 A2 A3 A4 Critical Path is
PLEASE SOLVE FOR ALL :)
determine ES, EF, LS, LF, and slack for each Dave Fletcher was able to determine the activity times for constructing his laser scanning machine. Fletcher would like activity. The total project completion time and the critical path should also be determined. Here are the activity times: Activity Time (weeks) Immediate Predecessor(s) Activity Time (weeks) Immediate Predecessor(s) E 4 A R 6 5 C A G 10 C, E D 1 A H 6 D.F Dave's...
Given this information about activity 3-4: ES = 10, EF = 15, LS = 16, and LF = 21, we can determine that the amount of slack associated with the activity is: 1. 5. 6. 11. 0.
Based on the following table, calculate the ES, EF, LS, LF and Slack for each activity using an expected completion time of 16 weeks. Please use the table format presented in the text to solve this problem. Please create one table with the original plan and a second table with the updates based on actual performance. What is the critical path for the original project? If the critical path changes as a result of actual progress, identify the new critical...
21. Using the CPM method, calculate early start (ES), late start (LS), early finish (EF), late finish (LF) and total float (TF) for each activity in the following network and answer the questions 21-1. The ES of activity His: a) 18 b) 22C) 5 d) 2 21-2. The LF of activity B is: a) 20 b) 22c) 18d) 19 ) 13 d) 59 21-3. The TF of activity A is: a) 5 b ) 17 c) 18 21-4. The project...
Question 24 (20 points) Use the following table of related activities with their activity times (weeks). Q24-1) Type your answers by the order of ES, EL, LS, LF, Slack for each activity. For example, A. Х, Х, Х, Х, Х Q24-2) Determine the critical path. Immediate Activity Activity Predecessor Time ESEFLSLqslack (weeks 4 C A DIB E A FIB G C,D H |D,F 7 6 5 4 6 G, H, I J
Question 24 (20 points) Use the following table...
CME403/603 Scheduling and Project Control (10 pts PDM) For the following PDM schedule, manually perform CPM calculation to show items as on legend (key) node - ES, EF, LS, LF, TF, SF and FNF. Highlight critical path(s). 2. 25 8 8 D 11 | 42 46 34 42 3 8 1 3 B 10 C T 16 10 18 29 40 37 Start Finis h 2 0 0 9 12 37 G 24 10 12 4 Legend ES Activity N...
Consider the following project where times are in weeks. Activity Duration Immediate Predecessors A B с D E F G H A.B B A с E,F 8 12 7 4 2 3 7 3 DF a) Determine the activity schedule (ES, EF, LS, and LF) as well as slack using the information from the table above (11 marks) b) Determine all the possible paths of this project and determine the shortest possible time this project can be completed? (4 marks)...
The ABC Manufacturing Co. has made a decision to replace an existing production line with new equipment. This project will require several tasks (jobs) with precedence relationships and duration (days) as shown in the following table. The project will be finished when activities A-J are all finished. Activity predecessor Optimistic Most likely Pessimistic Expected A - 4 5 12 B A 3 4.5 15 C A 2 3 4 D C 6 8 22 E B 4 6 8 F...