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Suppose that is the path which starts at the point (2,0), then moves along the circle4 to the point (0,2). Next, the path mov
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along人ive segnnernt from (0,9)to 14,3) (o2) (2,o) Now to porameteige cos ve AR, 0 at 0:0 →太)6大e-oった。 11 2 3 Amg hese values AB Jame passing through theトoints (o,2) and (4,3) Eguation of live though and (7,,y.): point6L 64| 7 A & 3 F, sof uwhere g is cemstamt ferNous differentia iang hoth Bide uith aesbat to y Js Jy dy し,3 ve get Ncw om fumdamental theorem of lime integral (4,3) 3 - 64

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