Question

19) Imagine that a particular polymer is found in one of two structures when deposited in a film. We will call the first polymer structure Orwellite. Under standard conditions, Orwellite converts into a more extended version called Kubnte in the reaction: Orwelite → Kubrite. StructureAH) (k/mol S° /mol K) AG (k/mol) 131 - 1984 Orwellite -300 70.0 2001 Kubritedata not given Use the data above to find AH for Kubrite in a laboratory that is 25.0 C and 1.00 atm A) -318 kJ/mol B) -18,495 kJ/mol C) -335 k/mol D) -1980 kJ/mol E) -1999 kJ/mol 20) What is the change in enthalpy when the pressure of 1.00 mole of H20 gas (steam) is decreased from 1.00 atm to 0.500 atm? The process occurs at a constant volume of 10.0 L You may treat H20 gas as an ideal gas; its value for Cv 25.3 J/(mol K) (Note: all numerical answers are given in kiloJoules.) A) -1.03 kJ B)-1.54 kJ C)0.0202 kJ D) -2.05 k E) Enthalpy cannot be found for a process that is not at constant pressure

The answer to 19 is C and the answer to 20 is D.

Answer 1

т- (273+25)-298K. 25°C Kub , (20+1948(10-131) XIO2 30187 410 oN, 4 335.178 Kjml Kub = _ 335 KJmot N-10 L 8.314 25.3 Cs Scanned with CamScanner

Again nR. 33.614 x 10 0-500-1-0 0 0.082 ー -2049.6 J _ 2.05 K s Scanned with CamScanner