Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔG∘: reaction A:reaction B:glucose-1-phosphatefructose-6-phosphate⟶⟶glucose-6-phosphate,glucose-6-phosphate, ΔG∘=−7.28 kJ/mol ΔG∘=−1.67 kJ/mol
Part A
Calculate ΔG∘ for the isomerization of glucose-1-phosphate to fructose-6-phosphate.
| ΔG∘ = |
-5.61 |
kJ/mol |
Part B
Calculate the equilibrium constant K for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 K.
Express your answer numerically using two significant figures.
| K = |
9.6 |
Part C
Calculate ΔG when the concentration of glucose-1-phosphate is 10 times greater than the concentration of fructose-6-phosphate.
Please help with Part C: calculate deltaG when [glucose-1-phosphate] is 10 times greater than [fructose-6-phosphate]
Homework Answers
Add Answer to:
Consider the following isomerization reactions of some simple
sugars and values for their standard Gibbs free energy
Δ...
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔG...
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔG∘: reaction A:glucose-1-phosphate⟶ glucose-6-phosphate, ΔG∘=−7.28 kJ/mol Reaction B: fructose-6-phosphate⟶⟶glucose-6-phosphate,ΔG∘=−1.67 kJ/mol Calculate the equilibrium constant K for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 K. Express your answer numerically using two significant figures.
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy :...
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy : Calculate for the isomerization of glucose-1-phosphate to fructose-6-phosphate. Answer: -5.61 >>>Calculate the equilibrium constant for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 .Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy Triangle G degree : Calculate for the isomerization of glucose-1-phosphate to fructose-6-phosphate. Answer: -5.61 >>>Calculate the equilibrium constant K for the isomerization...
The standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol . Calculate Δ? for this reaction...
The standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol .
Calculate Δ? for this reaction at 298 K when [dihydroxyacetone
phosphate]=0.100 M and [glyceraldehyde-3-phosphate]=0.00600 M .
Thank you!
For the aqueous reaction CH2OH Н— —он SO CH-0–_0 CH -0 - 0- dihydroxyacetone phosphate = glyceraldehyde-3-phosphate the standard change in Gibbs free energy is AGⓇ' = 7.53 kJ/mol. Calculate AG for this reaction at 298 K when [dihydroxyacetone phosphate) = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00600 M AG = kJ/mol
Calculate the standard change in Gibbs free energy, Δ?∘rxnΔGrxn∘ , for the given reaction at 25.0...
Calculate the standard change in Gibbs free energy, Δ?∘rxnΔGrxn∘ , for the given reaction at 25.0 ∘C25.0 ∘C . Consult the table of thermodynamic properties for standard Gibbs free energy of formation values. KCl(s)↽−−⇀K+(aq)+Cl−(aq)KCl(s)↽−−⇀K+(aq)+Cl−(aq) Δ?∘rxn= Determine the concentration of K+(aq)K+(aq) if the change in Gibbs free energy, Δ?rxnΔGrxn , for the reaction is −8.31 kJ/mol−8.31 kJ/mol . [K+]=
the enzyme hexokinase can catalyze the following reaction: fructose + ATP -> fructose 6 phosphate +...
the enzyme hexokinase can catalyze the following
reaction:
fructose + ATP -> fructose 6 phosphate + adp
if the deltaG of hydrolysis of fructose 6 phosphate to
fructose + Pi is -13.8 kj/mol and hydrolysis of atp to adp + pi is
-30kj/mol, calculate Keq for the reaction above (R = 8.31 j mol-1
K-1, T = 298 k
3a. The enzyme hexokinase can catalyze the following reaction: Fructose + ATP → Fructose-6-phosphate + ADP If the ΔGo of hydrolysis...
The standard free energy change (deltaG naught prime) for glucose 1-phosphate hydrolysis (i.e. glucose 1-phosphate +...
The standard free energy change (deltaG naught prime) for glucose 1-phosphate hydrolysis (i.e. glucose 1-phosphate + H2O --> glucose + phosphate) is -20.9 kJ/mol. If glucose and phosphate are both at 4.8 mM, what is the equilibrium concentration of glucose 1-phosphate at 25 deg C? Assume a gas constant of 8.314 J/mol K.
The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P)...
The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P): G6P F6P K = 0.510, at 298K. Calculate Delta G when Q, the [F6P|/[G6P] ratio, equals 10.0. times 10 J/mol Enter your answer in scientific notation.
For the aqueous reaction the standard change in Gibbs free energy is Delta G degree =...
For the aqueous reaction the standard change in Gibbs free energy is Delta G degree = 7.53 kJ/mol. Calculate Delta G for this reaction at 298 K when [dihydroxyacetone phosphate] = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00400 M. The constant R = 8.3145 J/(K middot mol) Delta G =
Calculate K at 298 K for the following reaction given the Gibbs free energy of formations...
Calculate K at 298 K for the following reaction given the Gibbs free energy of formations 213) substance! ΔG。 kJ/mol N2O4(g) +99.8 NO2(g)+51.3 1.13 0.32 3.1
Calculate the standard change in Gibbs free energy of the following reactions at Standard Ambient Temperature...
Calculate the standard change in Gibbs free energy of the
following reactions at Standard Ambient Temperature and Pressure
(SATP where T = 25°C and P = 1 atm) and label them as spontaneous
or nonspontaneous.
(a) 2 SO2(g) + O2(g) 2 SO3(g): ΔΗ.-197.8 k , dS.-188.0 J/K kJ, and the reaction is Selectv (b) 2 C6H6(/) + 15 O2(g) 12 CO2(g) + 6 H2O(/); ΔΗ.-6535.0 kJ, S.-439.2 J/K kJ, and the reaction is Select (c) C(diamond); C(graphite); ΔΗ--19 ki, as...
The standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol .
Calculate Δ? for this reaction at 298 K when [dihydroxyacetone
phosphate]=0.100 M and [glyceraldehyde-3-phosphate]=0.00600 M .
Thank you!
For the aqueous reaction CH2OH Н— —он SO CH-0–_0 CH -0 - 0- dihydroxyacetone phosphate = glyceraldehyde-3-phosphate the standard change in Gibbs free energy is AGⓇ' = 7.53 kJ/mol. Calculate AG for this reaction at 298 K when [dihydroxyacetone phosphate) = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00600 M AG = kJ/mol
the enzyme hexokinase can catalyze the following
reaction:
fructose + ATP -> fructose 6 phosphate + adp
if the deltaG of hydrolysis of fructose 6 phosphate to
fructose + Pi is -13.8 kj/mol and hydrolysis of atp to adp + pi is
-30kj/mol, calculate Keq for the reaction above (R = 8.31 j mol-1
K-1, T = 298 k
3a. The enzyme hexokinase can catalyze the following reaction: Fructose + ATP → Fructose-6-phosphate + ADP If the ΔGo of hydrolysis...
The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P): G6P F6P K = 0.510, at 298K. Calculate Delta G when Q, the [F6P|/[G6P] ratio, equals 10.0. times 10 J/mol Enter your answer in scientific notation.
For the aqueous reaction the standard change in Gibbs free energy is Delta G degree = 7.53 kJ/mol. Calculate Delta G for this reaction at 298 K when [dihydroxyacetone phosphate] = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00400 M. The constant R = 8.3145 J/(K middot mol) Delta G =
Calculate K at 298 K for the following reaction given the Gibbs free energy of formations 213) substance! ΔG。 kJ/mol N2O4(g) +99.8 NO2(g)+51.3 1.13 0.32 3.1
Calculate the standard change in Gibbs free energy of the
following reactions at Standard Ambient Temperature and Pressure
(SATP where T = 25°C and P = 1 atm) and label them as spontaneous
or nonspontaneous.
(a) 2 SO2(g) + O2(g) 2 SO3(g): ΔΗ.-197.8 k , dS.-188.0 J/K kJ, and the reaction is Selectv (b) 2 C6H6(/) + 15 O2(g) 12 CO2(g) + 6 H2O(/); ΔΗ.-6535.0 kJ, S.-439.2 J/K kJ, and the reaction is Select (c) C(diamond); C(graphite); ΔΗ--19 ki, as...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 10 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 10 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 10 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 10 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 10 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 10 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 10 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 10 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 10 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 10 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 10 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 10 months ago