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![[CO] [H20] [C02] [H2] initial 0.35 0.4 0 0 change -1x -1x +1x +1x equilibrium 0.35-1x 0.4-1x +1x +1x](http://img.homeworklib.com/questions/cd4d7760-1299-11ea-983d-075c7e172317.png?x-oss-process=image/resize,w_560)
Given at equilibrium,
[CO] = 0.22
0.35-1x = 0.22
x = 0.130
Equilibrium constant expression is
Kc = [CO2][H2]/[CO][H2O]
Kc = (+1x)(+1x)/(0.35-1x)(0.4-1x)
Kc = (+1*0.13)(+1*0.13)/(0.35-1*0.13)(0.4-1*0.13)
Kc = 0.28
Answer: C
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Please answer the following question and show all work to
receive credit:
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