Calculate the peak current in a 3.0?k? resistor connected to a 220-V rms ac source.
Ipeak= _________A
Vrms = V/sqrt(2)
So, V=Vrms*sqrt(2) = 220*sqrt(2) = 311.13V
Ipeak = V/R = 311.13/3000 = 0.1 A
Peak voltage
= 220 * sqrt(3) V
So
peak current
= 220 * sqrt(3) V / 3 kOhm = 127.010 mA.
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