Question

A new operator was recently assigned to a crew of workers who perform a certain job....

A new operator was recently assigned to a crew of workers who perform a certain job. From the records of the number of units of work completed by each worker each day last month, a sample of size five was randomly selected for each of the two experienced workers and the new worker. At the α = .05 level of significance, does the evidence provide sufficient reason to reject the claim that there is no difference in the amount of work done by the three workers?

Workers
New A B
Units of work (replicates) 9 10 11
8 12 9
10 10 11
9 11 12
9 12 9

(a) Find the test statistic. (Give your answer correct to two decimal places.)


(ii) Find the p-value. (Give your answer bounds exactly.)

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Answer #1

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: u1 = u2 = u3

Alternative hypothesis: At-least one of the u is not equal.

Formulate an analysis plan. For this analysis, the significance level is 0.05.

Analyze sample data.

squares sst dere sof means are|-statist F statistic p-value source squares SS freedom v MS treatment 10 10.5333 13.2000 23.7333 2 5.26674.78790.0296 error 12 1.1000 total 14

F statistics is given by:-

MSB MSE

F = 4.79

The P-value = 0.0296.

0.025 < p-value < 0.05.

Interpret results. Since the P-value (0.0296) is less than the significance level (0.05), we have to reject the null hypothesis.

Conclusion:-

Reject H0, There is sufficient evidence for significant difference in the amount of work done by the three workers.

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