Question

please answer 2 questions pleaeeee

#o: A 600-kg car traveling at 24.5 m/s is going around a curve having a radius of 120 m that is banked at an angle of 20°. (a) Draw a free body diagram (b) What is the reaction of the road on the car? (c) Is the curve properly banked for the car's speed? (d) What is the minimum coefficient of static friction required between the road and the car's tires so the car does not skid?

Answer 1

Cance Red K 120 a) En normal reaction force I Ff frictional force Mg Weight = Centrifugal force b) Equilibrium of forces ... I Normal to incline. Fu - Mg cas20° - Fe sin20°=0 V = 24.5mls Fu = mg cos 20° + mu? sin20° R=120m m= 600 kg • Fu = 60079.8.co%20° +(24.5) sine?? 8 = 9.8 m/s2 Er = 6651.00 c) For proper banking component of nonnal force must counter centrifugal force -) Fu sin 20° - Mu 6551.9N sin20° = 600x 24.5 2 2240.9 # 3001.25 Since alone by banking at 20° centrifugal force at this speed is not coundtered That is road is not properly banked for This speed. R

d) Along the incline Fc cos 20° - F - Mg sin 20° = 0 = F = E cos20° – Mg sin 20° - also Fq = MFN .: la mue cos20° - Mg sin2017 u = 600 kg 24.5mals)” cos20° – (9.8W/52) sin2o? He = 0.1235 655109N 120m