Question

The Separation of Three Organic Compounds by Acid, Base Reactions and Liquid, Liquid Extraction. Okay, so we had solid benzoic acid, ethyl 4- aminobenzoate, and 9-fluorenone all dissolved in diethyl ether. We separated the basic component by adding 3M HCl, we separated the acidic component by adding 3M NaOH. I don't understand what happens here. To isolate the acidic solution, we added 6 M NaOH and used the vacuum to recover the solid. To isolate the basic solution we added 6M HCl. I did an experiment where a 1:1:1 mixture of Benzoic Acid solid (C6H5COOH), ethyl 4-aminobenzoate solid (C9H11NO2), and 9-fluorenone solid (C13H8O) was dissolved with methylene chloride. Then each component was extracted and tested. I need to come up with a proton transfer chemical reaction that represents what happened in each separation. First separation: HCl was added and two layers formed. aqueous layer was extracted and transfer to a clean container and methylene chlotide layer was left aside. NaOH was added dropwise to aqueouse layer extraction and vacuum filtration was used to extract/separate the basic component ethyl 4-aminobenzoate solid (C9H11NO2)..... what can I say about this experiment in the disscusion

Answer 1

Sol: By adding 3M HCl to the reaction mixture containing benzoic acid, ethyl 4- aminobenzoate, and 9-fluorenone , ethyl 4- aminobenzoate reaction with HCl to form salt and seperated out. By adding 3M NaOH to the reaction mixture ,it react with benzoic acid,to form sodium benzoate salt and seperated out.The remaining 9-fluorenone, in reaction mixture is seperated by using liquid-liquid extraction method.By using this experiment you can say that,how to seperate the different substance,contain different natures like,acidic,basic and neutral fraom a reaction mixture.