The angular displacement of a torsional spring is proportional to the applied torque; that is τ = kθ, where k is a constant. Suppose that such a spring is mounted to an arm that moves in a vertical plane, The mass of the arm is 45.0 g, and it is 12.0 cm long. lhe arm-spring system is at equilibrium with the arm at an angular displacement of 17.0° with respect to the horizontal. If a mass of 0.420 kg is hung from the arm 9.00 cm from the axle, what will be the angular displacement in the new equilibrium position (relative to that with the unloaded spring)?
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