a)The current in the circuit shown in the figure is 0.20 A. What is the potential difference ΔVbat across the battery traveling in the direction shownin the first figure?
b)Find the current I in the circuit shown in the second figure.



The concepts required to solve the problem is Ohm’s law and finding the equivalent resistance for the combination of resistors.
First, find the potential difference across the battery using Ohm’s law. Then, find the current in the circuit by finding the resulting resistance and then by using Ohm’s law.
Ohm’s law is a relation connecting the current, voltage and resistance in an electric circuit. Ohm’s law states that the current through a conductor between two points is directly proportional to the potential difference across two points. The constant of proportionality is called the resistance of the circuit.
The expression for the ohm’s law is,

Here,
is the potential difference,
is the current, and
is the resistance.
When two resistors
and
are connected in series, the resultant resistance is,

(a)
According to Ohm’s law, the potential difference across the battery is,

Substitute
for
and
for
in the equation
to find the potential across the battery.

(b)
In the figure, the resistors are connected in series. For a series combination of resistors, the equivalent resistance is,

Substitute
for
and
for
in the equation
to find the equivalent resistance.

According to Ohm’s law, the current in the circuit is,

Substitute
for
and
for
to find 

The potential difference across the battery is
.
The current in the circuit is 
For the circuit shown in the figure find the current through
each resistor.
For the circuit shown in the figure find the potential
difference across each resistor.
A. For the circuit shown in the figure(Figure 1) find the
current through each resistor.
B. For the circuit shown in the figure find the potential
difference across each resistor.
24 V 4 Ω
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For the circuit shown in the figure (Figure 1), find the current through and the potential difference across each resistor. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution.
Review In the circuit shown in the diagram(Figure 1), suppose R1=R2 = 220 Ω and R3=R. The emf of the battery is 12.0 V . (A)Find the value of R such that the current supplied by the battery is 0.0900 A . (B)Find the value of R that gives a potential difference of 4.35 V across resistor 2.
For the RL circuit shown in Figure P32.17, let the
inductance be 3.00 H, the resistance 8.50 , and the battery emf 36.0 V.
Figure P32.17
(a) Calculate the ratio of the potential difference across the
resistor to that across the inductor when the current is 2.00
A.
ΔVR / ΔVL =
(b) Calculate the voltage across the inductor when the current is
4.50 A.
In the circuit shown in the diagram(Figure 1), suppose R1=R2 = 240 Ω and R3=R. The emf of the battery is 12.0 V . Find the value of R such that the current supplied by the battery is 0.0760 A . Find the value of R that gives a potential difference of 4.95 V across resistor 2.